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swimming-northbound:

this is literally all the motivation i would need 

swimming-northbound:

this is literally all the motivation i would need 

(Source: 0xytocinn, via supitslita)

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(Source: alwaysmadness, via yeahjor)

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"I always find myself caught between saying too much and not saying enough"

— H.M.L (via rhymez)

(Source: metaphxric, via shawnnarose)

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Photoset

bodies-behind-the-lens:

We expand and we grow, Its’ a part of being human, it’s a part of adapting to changes. Stretch marks and scars are a part of you, a part of the past that brought you to the stage you’re at right now. They are unique to you, and deserve to be embraced. 

Body Series © 

(via pizza-pirate)

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tyleroakley:

entropiaorganizada:

hookteeth:

… Y’see, now, y’see, I’m looking at this, thinking, squares fit together better than circles, so, say, if you wanted a box of donuts, a full box, you could probably fit more square donuts in than circle donuts if the circumference of the circle touched the each of the corners of the square donut.
So you might end up with more donuts.
But then I also think… Does the square or round donut have a greater donut volume? Is the number of donuts better than the entire donut mass as a whole?
Hrm.
HRM.

A round donut with radius R1 occupies the same space as a square donut with side 2R1. If the center circle of a round donut has a radius R2 and the hole of a square donut has a side 2R2, then the area of a round donut is πR12 - πr22. The area of a square donut would be then 4R12 - 4R22. This doesn’t say much, but in general and  throwing numbers, a full box of square donuts has more donut per donut than a full box of round donuts.The interesting thing is knowing exactly how much more donut per donut we have. Assuming first a small center hole (R2 = R1/4) and replacing in the proper expressions, we have a 27,6% more donut in the square one (Round: 15πR12/16 ≃ 2,94R12, square: 15R12/4 = 3,75R12). Now, assuming a large center hole (R2 = 3R1/4) we have a 27,7% more donut in the square one (Round: 7πR12/16 ≃ 1,37R12, square: 7R12/4 = 1,75R12). This tells us that, approximately, we’ll have a 27% bigger donut if it’s square than if it’s round.
tl;dr: Square donuts have a 27% more donut per donut in the same space as a round one.

Thank you donut side of Tumblr.

tyleroakley:

entropiaorganizada:

hookteeth:

… Y’see, now, y’see, I’m looking at this, thinking, squares fit together better than circles, so, say, if you wanted a box of donuts, a full box, you could probably fit more square donuts in than circle donuts if the circumference of the circle touched the each of the corners of the square donut.

So you might end up with more donuts.

But then I also think… Does the square or round donut have a greater donut volume? Is the number of donuts better than the entire donut mass as a whole?

Hrm.

HRM.

A round donut with radius R1 occupies the same space as a square donut with side 2R1. If the center circle of a round donut has a radius R2 and the hole of a square donut has a side 2R2, then the area of a round donut is πR12 - πr22. The area of a square donut would be then 4R12 - 4R22. This doesn’t say much, but in general and  throwing numbers, a full box of square donuts has more donut per donut than a full box of round donuts.

The interesting thing is knowing exactly how much more donut per donut we have. Assuming first a small center hole (
R2 = R1/4) and replacing in the proper expressions, we have a 27,6% more donut in the square one (Round: 15πR12/16 ≃ 2,94R12, square: 15R12/4 = 3,75R12). Now, assuming a large center hole (R2 = 3R1/4) we have a 27,7% more donut in the square one (Round: 7πR12/16 ≃ 1,37R12, square: 7R12/4 = 1,75R12). This tells us that, approximately, we’ll have a 27% bigger donut if it’s square than if it’s round.


tl;dr: Square donuts have a 27% more donut per donut in the same space as a round one.

Thank you donut side of Tumblr.

(Source: nimstrz, via damnitbrea)

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(Source: m3rrily, via sarahbethxx)